27x^2-15=60

Solution for 27x^2-15=60 equation:

27x^2-15=60

We move all terms to the left:

27x^2-15-(60)=0

We add all the numbers together, and all the variables

27x^2-75=0

a = 27; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·27·(-75)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*27}=\frac{-90}{54}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*27}=\frac{90}{54}
=1+2/3
$